Question

The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5. Suppose 49 golfers played the course today. Find the probability that the average score of the 49 golfers exceeded 62

a) 0.3707

b) 0.0228

c) 0.1293

d) 0.4772

Answer 1

Solution :

Given that ,

= 61

= / n = 3.5 / 49 = 0.5

P( > 62) = 1 - P( < 62)

= 1 - P[( - ) / < (62 - 61) / 0.5 ]

= 1 - P(z < 2.0)   

= 1 - 0.9772

= 0.0228

correct option is = b