Question

Historically, the average score of PGA golfers for one round is 71.1 with a standard deviation of 3.05. A random sample of 73 golfers is taken. What is the probability that the sample mean is greater than 71? Question 9 options: 1) 0.4869 2) 0.6103 3) 0.3897 4) 0.5131 5) -0.0746

Answer 1

Solution :

Given that ,

mean = = 71.1

standard deviation = = 3.05

n = 73

= 71.1 and

= / n = 3.05 / 73 = 0.357

P( > 71) = 1 - P( < 71)

= 1 - P(( - ) / < (71 - 71.1) / 0.357)

= 1 - P(z < -0.28)

= 1 - 0.3897

= 0.6103

Probability = 0.6103

2)