Historically, the average score of PGA golfers for one round is 71.1 with a standard deviation of 3.05. A random sample of 73 golfers is taken. What is the probability that the sample mean is greater than 71? Question 9 options: 1) 0.4869 2) 0.6103 3) 0.3897 4) 0.5131 5) -0.0746
Solution :
Given that ,
mean = = 71.1
standard deviation = = 3.05
n = 73
_{} = 71.1 and
_{} = / n = 3.05 / 73 = 0.357
P( > 71) = 1 - P( < 71)
= 1 - P(( - _{} ) / _{} < (71 - 71.1) / 0.357)
= 1 - P(z < -0.28)
= 1 - 0.3897
= 0.6103
Probability = 0.6103
2)
Get Answers For Free
Most questions answered within 1 hours.