Question

Let X be a discrete r.v. and Y be a continuous r.v. such that the conditional...

Let X be a discrete r.v. and Y be a continuous r.v. such that the conditional distribution of X given Y = y is a (discrete) geometric distribution with probability for success p, and such that Y has pdf f_Y(y) = 3y for 0 < y < 1 (and zero otherwise).

a) Compute the pmf of X.

b) Compute E[X].

c) Does the r.v. Var(X | Y) have a finite expectation?

Homework Answers

Answer #1

The PDF given in question f_Y(y) = 3y for 0 < y < 1 is wrong.

I take it as fY(y) = 3y2; 0 < y < 1

Given X is a discrete RV and Y be a continuous RV such that the conditional distribution of X given Y =y is geometric distribution with probability for success P.

So, the conditional PMF is

P (X = x | Y = y) = (1 – p)x p; x = 0,1,2,3…

So, X,Y are independent RVs.

Also, the PDF of Y is fY(y) n= 3y2; 0 < y < 1

The conditional expectation is E (X | Y) = (1 - p) / p

The joint mixture PDF is,

P (X = x, y) = P (X = x | Y = y) fY(y)

P (X = x, y) = (1 – p)xp(3y2)

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