The following numbers were randomly generated from a standard normal distribution: -0.25 , 0.3 , 1.5 , -1.2, -1.65, 1.5 1) Given interest rate = 0.01 and volatility parameter = 0.2, compute the drift parameter of a security following a risk-neutral geometric Brownian motion. 2). Suppose security ABC follows a geometric Brownian motion with the parameters given in 1). If the initial closing price of ABC S0 = S = 50, compute 6 more simulated daily closing prices for ABC. 3). If the strike price of a European call is = 52, and the expiration of this call is at the end of 6 days, what is the payoff of the call? That is, what is the value of (S6 ?K )+?
1)solution:
given data:
s = 50
= 0.01
= 0.2
assuming t is for 1 week so t value is
t = 0.0192
as per brownian process,
the formula of S/S = *t+*(root(t))
susbstitute the all values in above quation
S/50 = 0.01*0.0192+0.2**(root(0.0192))
S | 50 | ||||
0.01 | |||||
0.2 | |||||
t | 0.0192 | ||||
standard normal distributions are | -0.25 | 0.3 | -1.2 | -1.65 | 1.5 |
S | -0.33681 | 0.425292 | -1.65317 | -2.27671 | 2.088061 |
2) Stock price over a week as shown in below:
day | initial stock price | change in stock price | closing stock price |
1 | 50 | -.0336810162 | 49.66318984 |
2 | 49.66318984 | 0.425292194 | 50.08848203 |
3 | 50.08848203 | -1.653168775 | 48.43531326 |
4 | 48.43531326 | -2.276707066 | 46.15860619 |
5 | 46.15860619 | 2.088060969 | 48.24666716 |
6 | 48.24666716 | 0 | 48.24666716 |
3)
stock price | share price | pay off |
52 | 50 | 0 |
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