Assume all causes of failure of the system are totally independent:
Causes for System Failure |
Probability Failure |
Design |
.40 |
Practices and Procedures |
.20 |
Lack of Supervision |
.10 |
Lack of Training |
.30 |
Totals |
100% |
Assume all causes of failure of the system are totally independent:
Causes for System Failure |
Probability Failure |
Design |
.40 |
Practices and Procedures |
.20 |
Lack of Supervision |
.10 |
Lack of Training |
.30 |
Totals |
100% |
3. What is the probability that there is no error in the production of masks when a sample of 1,200 masks found that 100 were defective?
a) The probability that a computerized system fails due to a Lack of Training is seen directly from the given probability distribution table as: 0.3. therefore 0.3 is the required probability here.
b) The probability that a computerized system fails due to
Design or Supervision is computed here as:
= P(design) + P( supervision)
= 0.4 + 0.1 = 0.5
Therefore 0.5 is the required probability here.
c) Probability of no error here is computed as:
= Number of masks with no error/ Total masks produced
= (1200 - 100) / 1200
= 11/12
Therefore 11/12 is the required probability here.
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