Cystic fibrosis is a genetic disease caused by several variants of a gene. It is autosomal recessive. In other words, an individual must receive two copies of a cystic fibrosis genetic variant, one from the father and one from the mother, to manifest the condition. The probability that a child will be born with cystic fibrosis in the US is about 0.0004.
a. Assuming independent inheritance from the father and mother, what is the probability that any given copy of the gene will be a cystic fibrosis variant?
b. Calculate the probability that a given individual will be a
carrier, that is, have one copy of a cystic fibrosis variant.
c. Calculate the probability that a given individual will be
normal, that is, will have two copies of the normal gene.
The probability that a child will be born with cystic fibrosis in the US is about 0.0004.
a) Let the probability that any given copy of the gene will be a
cystic fibrosis variant is
. The probability that the child will get both the copies of the
gene is
. Given,
b) The probability of not being a carrier is
. The probability of being a carrier is (have one copy of a cystic
fibrosis variant)
c)The probability of not being a carrier is
. (They will have two copies of the normal gene)
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