Question

2. In a random sample of 360 females, 65% of them favored stricter gun control laws.

In another sample of 220 females, 60% of them favored stricter gun control laws.

Is there any significant difference between the proportions of male and female who

favored stricter gun control laws? Explain your answer.

Answer #1

In a random sample of 360 women, 65% favored stricter gun
control laws. In a random sample of 220 men, 60% favored stricter
gun control laws. Test the claim that the proportion of women
favoring stricter gun control is higher than the proportion of men
favoring stricter gun control. Use a significance level of
0.05.
Test and CI for Two Proportions
Sample X N Sample p
1 234 360 0.65
2 132 220 0.60
Difference = p (1) - p...

In a random sample of 360 women, 65% favored stricter gun
control laws. In a random sample of 220 men, 60% favored stricter
gun control laws. Test the claim that the proportion of women
favoring stricter gun control is higher than the proportion of men
favoring stricter gun control. Use a significance level of
0.05.
The test statistic is: (rounded to 2 decimal
places)
The p-value is: (rounded to 4 decimal
places)
The Conclusion

In a random sample of 360 women, 65% favored stricter gun
control laws. In a random sample of 220 men, 60% favored stricter
gun control laws. Test the claim that the proportion of women
favoring stricter gun control laws is higher than the proportion of
men favoring stricter gun control.
a) Write the claim and its opposite in symbolic form using the
proper notation.
b) Identify the Null and the Alternative hypotheses using
symbolic form.
c) Identify the significance level....

Historically, the percentage of U.S. residents who support
stricter gun control laws been 54%.A recent Gallup Poll of 1011
people showed 499 in favor of stricter gun 10% control laws. Assume
the poll was given to a random sample of people. Test the claim
that the proportion of those favoring stricter gun control has
fallen.
Perform a hypothesis test, using a significance level of 1%

California had stricter gun laws than Texas. However, California
had a greater proportion of gun murders than Texas. Here we test
whether or not the proportion was significantly
greater in California. A significant difference is one that is
unlikely to be a result of random variation. The table summarizes
the data for each state. The p̂'s are actually population
proportions but you should treat them as sample proportions. The
standard error (SE) is given to save calculation time if
you...

A random sample found that forty-three percent of 100 Americans
were satisfied with the gun control laws in 2017. Compute a 97%
confidence interval for the true proportion of Americans who were
satisifed with the gun control laws in 2017. Fill in the blanks
appropriately.
A 97% for the true proportion of Americans who were satisifed
with the gun control laws in 2017 is ( , )
(Keep 3 decimal places).
Can you please in include how the formula to solve?
n=...

For all hypothesis tests: Assume all samples are simple
random samples selected from normally distributed populations. If
testing means of two independent samples, assume variances are
unequal. For each test give the null and alternative hypothesis,
p-value, and conclusion as it relates to the claim.
In a random sample of 360 women, 65% favored stricter gun
control laws. In a random sample of 220 men, 60% favored stricter
gun control laws. Test the claim that the proportion of women
favoring...

Gun Murders - Texas vs New York - Significance
Test
In 2011, New York had much stricter gun laws than Texas. For that
year, the proportion of gun murders in Texas was greater than in
New York. Here we test whether or not the proportion was
significantly greater in Texas. The table below
gives relevant information. Here, the p̂'s are population
proportions but you should treat them as sample proportions. The
standard error (SE) is given to save calculation time...

Gun Murders - Texas vs New York - Significance
Test
In 2011, New York had much stricter gun laws than Texas. For that
year, the proportion of gun murders in Texas was greater than in
New York. Here we test whether or not the proportion was
significantly greater in Texas. The table below
gives relevant information. Here, the p̂'s are population
proportions but you should treat them as sample proportions. The
standard error (SE) is given to save calculation time...

A university financial aid office polled a random sample of 572
male undergraduate students and 644 female undergraduate students.
Each of the students was asked whether or not they were employed
during the previous summer. 307 of the male students and 389 of the
female students said that they had worked during the previous
summer. Give a 98% confidence interval for the difference between
the proportions of male and female students who were employed
during the summer. Step 1 of...

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