Question

A random sample found that forty-three percent of 100 Americans were satisfied with the gun control laws in 2017. Compute a 97% confidence interval for the true proportion of Americans who were satisifed with the gun control laws in 2017. Fill in the blanks appropriately.

A 97% for the true proportion of Americans who were satisifed with the gun control laws in 2017 is (  ,  ) (Keep 3 decimal places).

Can you please in include how the formula to solve?

n=	100
p=	0.43
qhat=	0.57
CL=	0.97
z=	1.881
	0.093124
lower=	0.336876
upper=	0.523124

That is what I keep getting....the answer is 0.323 and 0.523. What am I doing wrong?

Answer 1

Here,

sample proportion

and sample size

a 97% confidence interval for the true proportion of Americans who were satisified with the gun control laws in 2017