Question

A 2.9-kg cart is rolling along a frictionless, horizontal track
towards a 1.7-kg cart that is held initially at rest. The carts are
loaded with strong magnets that cause them to attract one another.
Thus, the speed of each cart increases. At a certain instant before
the carts collide, the first cart's velocity is +4.3 m/s, and the
second cart's velocity is -2.8 m/s. **(a)** What is
the total momentum of the system of the two carts at this instant?
**(b)** What was the velocity of the first cart when
the second cart was still at rest?

Answer #1

a) total momentum = m1u1 +m2u2 m1=2.9 kg u1=4.3 m/s m2= 1.7 kg u2 = -2.8 m/s

=2.9*4.3- 1.7*2.8 = 7.71 kgm/s

b) change in momentum = 2.8* 1.7 =4.76 = 2.9*(4.3-u)

u = 2.66 m/s

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