Question

# A 0.40 kg cart is moving at 3 m/s on a frictionless track where it collides...

A 0.40 kg cart is moving at 3 m/s on a frictionless track where it collides with a stationary 0.80 kg cart and two stick together. What is the final velocity of the pair ?

Masses of carts m1 = 0.4 kg

m2 = 0.8 kg

Initial Velocities of carts

V1 = 3 m/s

V2 = 0 (i.e, it is at rest)

Final velocity of the pair V = ?

From law of conservation of momentum,

m1 v1 + m2 v2 = (m1 + m2)V

m1 v1 + 0 = (m1 + m2)V

V = m1 v1/m1 + m2

= (0.4) (3)/ 0.4 + 0.8 = 1m1s

m1 v1 + m2 v2 = (m1 + m2)V

m1 v1 + 0 = (m1 + m2)V

V = m1 v1/m1 + m2

= (0.4) (3)/ 0.4 + 0.8 = 1m1s

m1 v1 + m2 v2 = (m1 + m2)V

m1 v1 + 0 = (m1 + m2)V

V = m1 v1/m1 + m2

= (0.4) (3)/ 0.4 + 0.8 = 1m1s

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