Question

If the work function of a material is 2.20 eV, what frequency of incident light would give a maximum kinetic energy of 0.25 eV to the photoelectrons ejected from the surface of this material? (1 eV = 1.60 × 10-19 J, h = 6.626 × 10-34 J ∙ s)

5.92 × 1014 Hz

3.53 × 1014 Hz

1.02 × 1014 Hz

2.50 × 1014 Hz

2.05 × 1014 Hz

Answer #1

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The work function for aluminum is 4.2 eV. (a) What is the cutoff
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