Question

The work function for aluminum is 4.2 eV. (a) What is the cutoff
frequency of light

incident on an aluminum target that releases photoelectrons from
its surface? (b) Find the

corresponding cutoff wavelength. (c) If photons of energy 5.0 eV
are incident on an

aluminum target what is the maximum kinetic energy of the ejected
photoelectrons? (d)

what is the maximum velocity of a photoelectron traveling from the
anode to the cathode

of a photocell? (d) If a blue beam with � = 500 nm hits the
aluminum target, what will

be the kinetic energy of the emitted photoelectrons?

Answer #1

Solution :

The work function for aluminum is 4.2 eV. (a) What is the cutoff
frequency of light
incident on an aluminum target that releases photoelectrons from
its surface? (b) Find the
corresponding cutoff wavelength. (c) If photons of energy 5.5 eV
are incident on an
aluminum target what is the maximum kinetic energy of the ejected
photoelectrons? (d)
what is the maximum velocity of a photoelectron traveling from the
anode to the cathode
of a photocell? (d) If a red laser...

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a beam of photons strikes a photoelectric cell with a work
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if light with a frequency of 1*10^15 hz falls on the sodium in
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c) Light...

If the work function of a material is 2.20 eV, what frequency of
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5.92 × 1014 Hz
3.53 × 1014 Hz
1.02 × 1014 Hz
2.50 × 1014 Hz
2.05 × 1014 Hz

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(a) What is the maximum kinetic energy of the emitted electrons,
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(b)What is the maximum velocity of the emitted electrons, in
m/s?
(c) What is the stopping potential, in Volts, that results in no
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Hz
nm
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eV
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eV

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wavelength
_________ nm
frequency
_________ Hz
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_________________V

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light of wavelength of
(a) 310 nm and (b) 460 nm.

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