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A weighted string 1 meter long is shown to have a standing wave when v is...

  1. A weighted string 1 meter long is shown to have a standing wave when v is equal to 220. The frequency is 11o Hz and is the fundamental frequency. Find the next 3 Overtones and the first 3 harmonics.
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Answer #1

Length of the strinng (L) = 1m

velocity (v)= 220

fundamentnal frequency (f) = 110 Hz

we, know fn= vn/2l

given fundamental frequency (f1) =110HZ

first overtone (f2)= 2V/2l= v/l = 220/1= 220Hz

second overtone (f3)= 3V/2l= 3*220/2*1= 330Hz

third overtone (f4)= 4V/2l= 2v/l= 2*220/1= 440Hz

Now, for harmonic (), we can use the relation = 2l/n (l= length of the string)

so, for first harmonic () = 2l/1= 2l= 2*1= 2m

second harmonic () = 2l/2= l =1m

third harmonic ()= 2l/3= 2*1/3= 0.6m

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