An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only a rope and a bag of tools. First he tries to throw a rope to his fellow astronaut, but the rope is too short. In a last ditch effort, the astronaut throws his bag of tools in the direction of his motion (away from the space station). The astronaut has a mass of 102 kg and the bag of tools has a mass of 10.0 kg. If the astronaut is moving away from the space station at 2.40 m/s initially, what is the minimum final speed of the bag of tools (with respect to the space station) that will keep the astronaut from drifting away forever?
You need apply the momentum conservation for resolve this problem.
First you know that astronaut has a mass 102 kg and his velocity with the bag is 2.4 m/s before throw the bag. you know the mass of the bag which is 10 kg. Then you can apply the momentum conservation
where m1 is the mass astronaut and m2 is mass bag. And the velocity v1 is the velocity of the astronaut and v2 is the velocity bag
The velocity the astronaut and the bag is 2.4 m/s before throw its bag, and for keep the astronaut from drifting away forever his velocity must be zero, then we have the following
If you have any question please let me know the comments
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