Question

Two balls of the same size same volume are released from the same height at the same time. Ball 1 is simply dropped (initial velocity is zero)Ball 2 has initial velocity, v=2.0 m/s parallel to the ground

If the ball has same mass which ball will hit the ground first? Explain

If the balls have the same mass, which ball will hit the ground with a higher velocity? explain

In a case where ball 1 has mass m1=0.5 kg and ball 2 has mass m2=0.7kg, which ball would hit the ground first? . Explain

In a case where ball 1 has mass m1=0.5 kg and ball 2 has mass m2=0.7kg, which ball would hit the ground with a higher velocity? Explain

In a case where ball 1 has mass m1=0.7 kg and ball 2 has mass m2=0.5kg, which ball would hit the ground first? Explain

In a case where ball 1 has mass m1=0.7 kg and ball 2 has mass m2=0.5kg, which ball would hit the ground with a higher velocity? Explain

Answer 1

As you know gravity acceleration work here which is downward.

Both ball has same acceleration g downward direction .

Since g is independent from the mass of the object. So both ball reach at the same time.

- downward component of the velocity V =sqrt(2gh)

Using Newton law of motion (sqrt =square root)

V=sqrt(2gh)

Velocity of the first ball V=sqrt(2gh).....1

Velocity of the second ball.

V=sqrt((2gh)^2+(2)^2)

V=sqrt ((2gh)^2+4)

It also has parallel component.

All of these things are independent of the mass.

So

Reaching time at ground will be same .

comparing equation 1 and 2

Ball 2 has higher velocity at ground.