Question

A plastic plano-concave lens has a radius of curvature of 58 cm for its concave surface....

A plastic plano-concave lens has a radius of curvature of 58 cm for its concave surface. If the index of refraction of the plastic is 1.25, what is the power of the lens?

Homework Answers

Answer #1

Solution:

Let us go to the basics first.

The lens maker's formula is:

1/f =( n-1){(1/R1) - (1/R2)},

where n is the refractive index of the material of the lens with respect to the medium in which it is placed, R1, R2 are radii of curvature of the two surfaces of the lens.

Given that the refractive index of material of the lens = 1.25, and R1 =58 cm and R2= infinity ( for the plane surface),

Substituting, these values we get,

1/f =( 1.25-1){(1/58) - 0},

=>f =232 cm =232/100 m =2.32 m

Therefore power of the lens=1/2.32 = 0.431 diopter           (Answer)

Thanks!!!

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A plano-concave cylindrical lens is used to form an image of a point object 24 cm...
A plano-concave cylindrical lens is used to form an image of a point object 24 cm from the lens. The lens has a refractive index of 1.50, a radius of curvature 12 cm and an axial length of 6cm. A) what is the power of the cylindrical lens? B)what is the location of the image line? C) is it real/virtual? D)what is the length of the image line?
One side of a lens is concave with the radius of curvature of 25cm, and the...
One side of a lens is concave with the radius of curvature of 25cm, and the other side is flat. The lens is made of glass with index of refraction of 1.5. Find the focal power of the lens? What is the type of lens (coverging or diverging)?
Rays pass through a semi-circular, plano-convex lens with a radius of curvature of 7.62 cm. As...
Rays pass through a semi-circular, plano-convex lens with a radius of curvature of 7.62 cm. As light rays incident on the flat side of the lens and exit through the circular side, a ray incident along a line parallel to the axis of the lens is 2.00 cm above or below that axis would converge to a focus 18.90 cm from the geometric center of the lens. What is the effective index of refraction for the material the lens is...
1) A plano-convex lens having a radius of curvature of r = 2.20 m is placed...
1) A plano-convex lens having a radius of curvature of r = 2.20 m is placed on a concave glass surface whose radius of curvature is R = 13.0 m as shown in the figure below. Assuming 515-nm light is incident normal to the flat surface of the lens, determine the radius of the 100th bright ring. cm 2) Light of wavelength 589.0 nm illuminates a slit of width 0.80 mm. (a) At what distance from the slit should a...
A concave mirror that has a radius of curvature equal to 55.0 cm is oriented with...
A concave mirror that has a radius of curvature equal to 55.0 cm is oriented with its axis vertical. The mirror is filled with anise oil that has an index of refraction equal to 1.54 and a maximum depth of 1.50 cm. An object is placed at 7.00 cm above the vertex of the mirror. (a) Where is the intermediate image formed by the anise oil lens? What is the lateral magnification of this image? (b) Where is the image...
A thin plastic lens with index of refraction n = 1.64 has radii of curvature given...
A thin plastic lens with index of refraction n = 1.64 has radii of curvature given by R1 = ?10.0 cm and R2 = 45.0 cm. (a) Determine the focal length in cm of the lens. cm (b) Determine whether the lens is converging or diverging. Determine the image distances in cm for object distances of infinity, 3.00 cm, and 30.0 cm. (c) infinity   (d) 3.00 cm (e) 30.0 cm
The radius of the curvature of one of the surfaces of a biconvex lens is 5...
The radius of the curvature of one of the surfaces of a biconvex lens is 5 times superior to the other radius on the other side. the lens is made of glass with a refraction index of 1.53, the power is 5D. Determine the radius of curvature on both sides. I used the equation of the Lensmaker's Equation for a Thick Lens, but i cant match the answer give, which is R1=12,7mm and R2=-63,5mm.
1. A 3.50 mm object is placed 13.0 cm in front of a lens that has...
1. A 3.50 mm object is placed 13.0 cm in front of a lens that has a focal length of -6.50 cm, a second lens is 25.0 cm from the first and has a focal length of 9.00 cm. What is the final height of the image formed, is it virtual or real? 2. Assuming the lenses of a person's eyeglasses are 2.10 cm from their eyes, what power of lens must be used to correct the vision of a...
A single bi-concave lens (a lens with two concave surfaces) made of fused quartz (index of...
A single bi-concave lens (a lens with two concave surfaces) made of fused quartz (index of refraction n = 1.46) has surfaces with radii of curvature r1 = -27.0 cm and r2 = 27.0 cm. a)What is the focal length of the lens in air? b)If an object is placed at p = 14.0 cm from the lens, where is the image? (Use a positive sign for a real image or a minus sign for a virtual image.) c)If the...
a) A single bi-concave lens (a lens with two concave surfaces) made of fused quartz (index...
a) A single bi-concave lens (a lens with two concave surfaces) made of fused quartz (index of refraction n = 1.46) has surfaces with radii of curvature r1 = -12.0 cm and r2 = 12.0 cm. What is the focal length of the lens in air? b) If an object is placed at p = 20.0 cm from the lens, where is the image? (Use a positive sign for a real image or a minus sign for a virtual image.)...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT