Question

A concave mirror that has a radius of curvature equal to 55.0 cm is oriented with its axis vertical. The mirror is filled with anise oil that has an index of refraction equal to 1.54 and a maximum depth of 1.50 cm. An object is placed at 7.00 cm above the vertex of the mirror.

(a) Where is the intermediate image formed by the anise oil lens? What is the lateral magnification of this image?

(b) Where is the image formed by the concave mirror? What is the lateral magnification of this image?

(c) Where is the image formed by the anise oil lens again, after light reflects the mirror? What is the lateral magnification of this image?

(d) Where are the position and the lateral magnification of the final image?

Answer 1

b) image formed by concave mirror

1/f=1/v+1/u

-2/55=1/v+1/(-7) [f of concave mirror is negative, f=-R/2] [u=-7cm]

we get, v=9.39 cm

lateral magnification=m=-v/u

m=-9.39/7= -1.34 [-ve sign indicates real and inverted image]