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Rays pass through a semi-circular, plano-convex lens with a radius of curvature of 7.62 cm. As...

Rays pass through a semi-circular, plano-convex lens with a radius of curvature of 7.62 cm. As light rays incident on the flat side of the lens and exit through the circular side, a ray incident along a line parallel to the axis of the lens is 2.00 cm above or below that axis would converge to a focus 18.90 cm from the geometric center of the lens. What is the effective index of refraction for the material the lens is made out of? Answer in step-by-step format, clearly list equations and reasoning and explain why your answer makes logical sense.

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