Eight identical spherical raindrops are each at an electric potential of 8 V, relative to the potential far away. Without losing charge or volume, they coalesce to make one spherical raindrop. What is the potential of the larger raindrop?
Ans: 32 V
Explanation:
Let the charge of each small raindrop is q and radius r.
so, potential due to each small raindrop , V = kq/r
Now when 8 raindrops make a large raindrops , without loosing charge and volume ,
Let the radius of large raindrop is R and charge is Q.
Now , volume of large raindrop ,
Volume of each small raindrop ,
Also , the charge of large raindrop , Q = 8q
So potential due to large raindrop ,
V' = kQ/R = k(8q)/(2r) = 4×kq/r = 4V
Now potential of each small raindrop is 8 V.
So potential of larger raindrop is (4×8) V = 32 V.
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