What power, is dissipated in 21.8 μs by 0.59×1015 electrons ejected from a material by 123 nm photons, if they are bound to the material by 4.53 eV?
Given:
Binding Energy = 4.53 eV
Photon Energy is given by
Substituting the known values yields
We can convert this into eV by using the relation
Now, we can calculate the energy of the electron ejected from the metal by the photon using the relation
This is the energy of 1 electron. We can calculate the energy of 0.59x1015 electrons by multiplying by this number.
Total energy of electrons = 3.22 x 1015 eV
Power can be calculated using the relation P = Work done (or energy dissipated) per unit time
Therefore,
To calculate the power in Watts, we will convert eV to J:
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