Question

What power, is dissipated in 21.8 μs by 0.59×1015 electrons ejected from a material by 123...

What power, is dissipated in 21.8 μs by 0.59×1015 electrons ejected from a material by 123 nm photons, if they are bound to the material by 4.53 eV?

Homework Answers

Answer #1

Given:

Binding Energy = 4.53 eV

Photon Energy is given by

Substituting the known values yields

We can convert this into eV by using the relation

Now, we can calculate the energy of the electron ejected from the metal by the photon using the relation

This is the energy of 1 electron. We can calculate the energy of 0.59x1015 electrons by multiplying by this number.

Total energy of electrons = 3.22 x 1015 eV

Power can be calculated using the relation P = Work done (or energy dissipated) per unit time

Therefore,

To calculate the power in Watts, we will convert eV to J:

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