The equilibirum constant (k) for an amino acid acting as an acid-base pair in solution is:
AA + H2O <--------> H3O+ + AA- k = 9.03 E -5
Calculate the absorbance at 433 nm for the solution if the initial AA concentration of 4E-4 M, given that ɛAA = 9.04 E3 M and ɛAA- = 0.855 E3 M
Here, absorbance = e * L * c
where, e = molar extinction coefficient
L = path length of the cell holder
c = concentration of the solution
=> absorbance = 9.03 * 10-5 * 433 * 10-9 * 4 * 10-4
= 1.564 * 10-14
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