Find the H3O+ concentration of a 0.210 M hypochlorous acid solution (whose acid dissociation constant is Ka=2.9×10−8).
hypochlorous acid dissociated as
HClO + H2O
H3O+ + OCl-
it is monoprotic acid therefore [ H3O+ ] = [OCl-]
Ka = [ H3O+ ] [OCl-] / [HClO]
consider [ H3O+ ] = [OCl-] = X
then above equation become
Ka = X2 / [HClO]
substitute value
2.9 10-8
= X2 / 0.210
X2 = 2.9
10-8
0.210
X2 = 6.09
10-9
X = 7.8 10-5
= [ H3O+ ] = [OCl-]
concentration of H3O+ = 7.8
10-5
M
Get Answers For Free
Most questions answered within 1 hours.