Find the H3O+ concentration of a 0.210 M hypochlorous acid solution (whose acid dissociation constant is Ka=2.9×10−8).
hypochlorous acid dissociated as
HClO + H2O H3O+ + OCl-
it is monoprotic acid therefore [ H3O+ ] = [OCl-]
Ka = [ H3O+ ] [OCl-] / [HClO]
consider [ H3O+ ] = [OCl-] = X
then above equation become
Ka = X2 / [HClO]
substitute value
2.9 10-8 = X2 / 0.210
X2 = 2.9 10-8 0.210
X2 = 6.09 10-9
X = 7.8 10-5 = [ H3O+ ] = [OCl-]
concentration of H3O+ = 7.8 10-5 M
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