What minimum heat is needed to bring 200 g of water at 40 ∘C to the boiling point and completely boil it away? The specific heat of water is 4190 J/(kg⋅K) and its heat of vaporization is 22.6×105 J/kg.
Specific heat of water = 4190 Joules/kg-C
Heat of vaporization of water = 22.6 x 10^5 Joules/kg.
<< What minimum heat is needed to bring 200 g of water at 40
C to the boiling point >>
Q1 = heat required to bring water to a boil
Q1 = (200/1000)(4190)(100 - 40)
Q1 =50280 joules
Q2 = heat required for water to become steam
Q2 = (200/1000)(22.6 x 10^5) = 452,000 joules
Therefore, the total heat required to satisfy the conditions of the
problem is
Q = Q1 + Q2
Q = 502280 joules
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