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Two children want to use a see-saw. The mass of the first child is 35 kg,...

Two children want to use a see-saw. The mass of the first child is 35 kg, and the mass of the second child is 50 kg. The see-saw is a 4.8 m long, with its center balancing on a fulcrum. The 35 kg child sits on the very end of his side of the see-saw. Where should the second child sit so that the see-saw balances evenly? The answer is :1.68 m from the center on the opposite side

Can you show me clearly what equations you used? Thanks!

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Answer #1

Gravitational acceleration = g = 9.81 m/s2

Mass of the first child = m1 = 35 kg

Mass of the second child = m2 = 50 kg

Length of the see-saw = L = 4.8 m

The fulcrum is at the center of the see-saw and the first child sits at one end of the see-saw.

Distance of the first child from the fulcrum = L/2

Distance of the second child from the fulcrum = D

Taking moment balance about the fulcrum,

m1g(L/2) = m2gD

m1(L/2) = m2D

(35)(4.8/2) = (50)D

D = 1.68 m

To balance the see-saw the second child should sit on the opposite side at a distance of 1.68 m from the center.

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