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Two children are balanced on a seesaw that has a mass of 19.0 kg. The first...

Two children are balanced on a seesaw that has a mass of 19.0 kg. The first child has a mass of 26.0 kg and sits 1.60 m from the pivot. The center of mass of the seesaw is 0.113 m from the pivot (on the side of the first child).

(a) If the second child has a mass of 31.8 kg, how far (in m) is she from the pivot?

(b) What is the supporting force (in N) exerted by the pivot?

I tried following other Chegg answers on this one with different numbers and I can't seem to get it correct or understand it.

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Answer #1

(b) supporting force:

considering equilibrium in vertical direction

R = 26 x g + 19 x g + 31.8 x g;

= 76.8 x g

= 76.8 x 9.81

= 753.408 N

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