Given that the atomic number of zinc is 30, and the atomic mass is 65 grams/mole, what is the net charge of just the protons in 7.3 kg of zinc?
atomic mass of zinc is 65 grams/mole.
Number of moles in 7.3 kg (7300g ) of zinc = 7300g / 65 grams/mole = 112.30 moles
Avogadro's number --1 mole = 6.022×10 ^23 atoms
Number of atoms ( in 7.3 kg of zinc) =112.30 moles * 6.022= 676.31 ×10 ^23 atoms
Given that the atomic number of zinc is 30 that means one atom of zinc contains 30 protons.
Number of protons ( in 7.3 kg of zinc) =676.31 ×10 ^23 atoms * 30 = 20,289.507 ×10 ^23 protons
charge of one proton = 1.6 x10^-19 C
the net charge of protons in 7.3 kg of zinc =20,289.507 ×10 ^23 protons * 1.6 x10^-19 C = 3.246 C
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