A 6.0-mm-diameter proton beam carries a total current of 1.4 mA . The current density in the proton beam, which increases with distance from the center, is given by J=Jedge(r/R) , where R is the radius of the beam and Jedge is the current density at the edge.
Part A.
How many protons per second are delivered by this proton beam?
Part B.
Determine the value of Jedge.
i hope it will clear all your doubts please comment if you have any further question
please rate positively
Get Answers For Free
Most questions answered within 1 hours.