Question

A person with mass m_{p} = 75 kg stands on a spinning
platform disk with a radius of R = 1.65 m and mass m_{d} =
187 kg. The disk is initially spinning at ω = 1.4 rad/s. The person
then walks 2/3 of the way toward the center of the disk (ending
0.55 m from the center).

1) What is the total moment of inertia of the system about the center of the disk when the person stands on the rim of the disk?

2) What is the total moment of inertia of the system about the center of the disk when the person stands at the final location 2/3 of the way toward the center of the disk?

3) What is the final angular velocity of the disk?

4) What is the change in the total kinetic energy of the person and disk? (A positive value means the energy increased.)

5) What is the centripetal acceleration of the person when she is at R/3?

6) If the person now walks back to the rim of the disk, what is the final angular speed of the disk?

Answer #1

A person with mass mp = 79 kg stands on a spinning
platform disk with a radius of R = 1.83 m and mass md =
183 kg. The disk is initially spinning at ω = 1.8 rad/s. The person
then walks 2/3 of the way toward the center of the disk (ending
0.61 m from the center).
1)
What is the total moment of inertia of the system about the
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0.74 m from the center).
1)
What is the total moment of inertia of the system about the
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A person with mass mp = 72 kg stands on a spinning
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A. Calculate the angular velocity when the person reaches the edge.
B. Calculate the rotational kinetic energy of the system of
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1. A person of mass 75.0 kg stands at the center of a rotating
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A disk with mass m = 8.5 kg and radius R = 0.35 m begins at rest
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c) What is the moment of inertia of the disk?
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A disk with mass m = 9.5 kg and radius R = 0.3 m begins at rest
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A)What is the angular acceleration of the disk?
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A person of mass 72 kg stands at the center of a rotating
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