Question

- An object 20. cm to the left of
**a convex lens**is 1.0 m in height. What is the height and location of its image if the lens has a magnification of**-2.0**? ________________ m and ________________ cm on the (*left / right )*side of the lens*(5 pts)*

**[Show your work]**

Answer #1

A small object is placed to the left of a convex lens and on its
optical axis. The object is 30 cm from the lens, which has a focal
length of 49 cm. If the object is moved to a position 57 cm away,
what will the image position be? (A positive value for p,
or position, means the image is on the right side of the lens.)
p = ? cm
Describe the nature of this new image. (Select...

An object of height 6.00 cm is placed 24.0 cm to the left of a
converging lens with a focal length of 10.5 cm. Determine the image
location in cm, the magnification, and the image height in cm.
(a) the image location in cm
(b) the magnification
(c) the image height in cm
(d) Is the image real or virtual?
(e) Is the image upright or inverted?

Principal Ray Diagrams and Equations
1.) An object is 6 cm in front of a convex mirror with a focal
length of 10 cm.
a.) Use ray tracing alone to determine the location and
magnification of the image. Is the image upright or inverted? Is it
real or virtual?
b.) Use equations alone to determine the location and
magnification of the image. Is the image upright or inverted? Is it
real or virtual?
2.) A 2.0-cm-tall object is 20 cm...

A convex lens with a focal length of magnitude 4.0 cm and a
concave lens with a focal length of magnitude 10 cm are separated
by a distance of 18 cm as shown in the diagram below. The convex
lens is on the left, and the concave lens is on the right. An
object is then placed 6.0 cm to the left of the convex lens.
Locate the final image. State the distance of the final image
to the right...

An object is 17.4 cm to the left of a lens with a focal
length of 12.4 cm. A second lens of focal length 14.7
cm is 54.91 cm to the right of the first lens.
The height of the object of is 3.6 cm.
What is the location of the final image with respect to the
second lens?
What is the height of the image?
Also determine is the image real or virtual and, with
respect to the original...

An
object is placed 30 cm to the left of a converging lens of focal
length 10 cm. A diverging lens of focal length -15 cm is 20 cm to
the right of the converging lens.
a) Where is the image created by the first lens relative to
the first lens?
b) Is it real or virtual?
c) Where is the final image relative to the second lens?
d) Is it real or virtual?
e) What is the final lateral...

Consider a convex lens with a focal length of 5.00 cm. An object
is located at 12.50 cm. The object is 5.50 cm tall. Draw the ray
diagram to scale. Determine the image distance, the height of the
image, the magnification and the characteristices of the image.

An object with a height of 47 cm is placed 2.0 m in front of a
convex mirror with a focal length of -0.46 m .
A:
Find the location of the image produced by the mirror using the
mirror and magnification equations. (answer in Meters)
B:
Is it 1. In front of the mirror or 2. behind the mirror.
C:
Find the magnification of the image produced by the mirror using
the mirror and magnification equations.

A 1.9-cm-tall object is 20 cm to the left of a lens with a focal
length of 10 cm . A second lens with a focal length of -7 cm is 34
cm to the right of the first lens.
Calculate the distance between the final image and the second
lens.
Calculate the image height.

An
object is at the 10 cm mark, the 20 cm convex lens (objective) is
at the 80 cm mark and the 10 cm lens (eyepiece) is placed at the
114 cm mark. What is the maximum magnification this telescope could
provide? What would you have to change to improve the magnification
of your telescope?

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