Question

An object is 17.4 *cm* to the left of a lens with a focal
length of 12.4 *cm*. A second lens of focal length 14.7
*cm* is 54.91 *cm* to the right of the first lens.
The height of the object of is 3.6 *cm*.

**What is the location of the final image with respect to the
second lens?
What is the height of the image?**

**Also determine is the image real or virtual and, with
respect to the original object, upright or inverted? Check all
statements that are true.**

The image is inverted

The image is virtual

The image is upright

The image is real

Answer #1

Given,

o1 = 17.4 cm ; f1 = 12.4 cm ; f2 = 14.7 cm ; D = 54.91 cm ; ho = 3.6 cm

We know from lens eqn

1/f = 1/i + 1/o

i = o x f/(o - f)

i1 = 17.4 x 12.4/(17.4 - 12.4) = 43.15 cm

o2 = D - i1

o2 = 54.91 - 43.15 = 11.76 cm

i2 = 11.76 x 14.7/(11.76 - 14.7) = -58.8 cm

Hence, i2 = -58.8 cm

we know that

M = -i/o

m1 = -43.15/14.7 = -2.48

m2 = -(-58.8)/11.76 = 5

M = m1 m2 = -2.48 x 5 = 12.4

h' = 12.4 x 3.6 = 44.64 cm

Hence, h' = 44.64 m

The image is virtual and inverted.

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