A box with a square base and open top must have a volume of
157216 cm3cm3. We wish to find the dimensions of the box that
minimize the amount of material used.
First, find a formula for the surface area of the box in terms of
only xx, the length of one side of the square base.
[Hint: use the volume formula to express the height of the box in
terms of xx.]
Simplify your formula as much as possible.
A(x)=A(x)=
Next, find the derivative, A'(x)A′(x).
A'(x)=A′(x)=
Now, calculate when the derivative equals zero, that is, when
A'(x)=0A′(x)=0. [Hint: multiply both sides by x2x2.]
A'(x)=0A′(x)=0 when x=x=
We next have to make sure that this value of xx gives a minimum
value for the surface area. Let's use the second derivative test.
Find A"(x)(x).
A"(x)=(x)=
Evaluate A"(x)(x) at the xx-value you gave above.
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