Find the equation of the tangent line to y= cos x at x= pi/2
Solution: Given the curve:
The objective is to find the equation of the tangent to this curve at x = /2. The value of the y-coordinate at this x can be calculated as:
Therefore, (0,/2) is the point of tangency. Now, to find the slope of the tangent, we'll find the derivative of the function w.r.t x at the point of tangency, we'll get:
Therefore,
Equation of a line in the point-slope form is given by:
Substituting the point of tangency and the slope, we'll get:
Thus, we got the equation of tangent to the given curve.
I hope it helps you!
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