Question

Find the equation of the tangent line to the curve y = 3 sec x - 6 cos x at the point (pi/3, 3). The equation must be written in y = mx + b form

find m and b

Answer #1

Find an equation of the tangent line to the curve at the given
point. A) y = 6x + 3 cos x, P = (0, 3) B)y = 8 x cos x P = \(pi ,
-8 pi)
B)Find an equation of the tangent line to the curve at the given
point.
y = 8 x cos x
C)
If H(θ) = θ cos θ, find H'(θ) and H''(θ).
find H'(
θ)
and H"(θ)

4) Use implicit differentiation to find the equation of the
tangent line to the curve xy^3+xy=16 at the point (8,1). The
equation of this tangent line can be written in the form
y=mx+by=mx+b where m is:
and where b is:

Find an equation of the tangent line to the curve at the given
point.
1.) y= sqrt(5x+ 9), at x= 10.
2.) y= cos(x) + cos^3(x), at x=π/6.

Find an equation of the tangent line to the curve at the given
point.
y = sec(x), (π/3, 2)

Find an equation for the line tangent to the curve at the point
defined by the given value of t. Also, find the value of
d2y/dx2 at this point.
x= sec2t-1 , y= cos(t) , t= pi/4

Use implicit differentiation to find an equation of the line
tangent to the curve sin(x+y)=2x-y at the point (pi,2\pi )

Find the slope of the line tangent to the curve y=x^2 at the
point (-0.9,0.81) and then find the corresponding equation of the
tangent line.
Find the slope of the line tangent to the curve y=x^2 at the
point (6/7, 36,49) and then find the corresponding equation to the
tangent line.
answer must be simplified fraction

3. Find the equation of the tangent line to the curve 2x^3 + y^2
= xy at the point (−1, 1).
4. Use implicit differentiation to find y' for sin(xy^2 ) − x^3
= 4x + 2y.
5. Use logarithmic differentiation to find y' for y = e^4x
cos(2x) / (x−1)^4 .
6. Show that d/dx (tan (x)) = sec^2 (x) using only your
knowledge of the derivatives of sine/cosine with derivative
rules.
7. Use implicit differentiation to show that...

Use implicit differentiation to find an equation of the line
tangent to the curve sin(x+y)=2x-y at the point (pi, 2pi )

a) Find the equation of the tangent line to the curve x= 2sin2t,
y= 3sint at the point where the same.
b) Find the points on the curve x= t^2-t+2, y=t^3-3t where the
tangent is horizontal.

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