(1 point) Let F⃗ =(24a2x+2ay2)i⃗ +(2z3−6ay)j⃗ −(3z+2x2+2y2)k⃗ F→=(24a2x+2ay2)i→+(2z3−6ay)j→−(3z+2x2+2y2)k→.
(a) Find the value(s) of aa making div F⃗ =0div
F→=0
a=a=
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comma-separated list of your values.)
(b) Find the value(s) of aa making div F⃗ div
F→ a minimum
a=a=
(Enter your value, or if you have more than one, enter a
comma-separated list of your values.)
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