Question

I=interval with rl #'s which has x=0. f(x) is an odd function that is differentiable on...

I=interval with rl #'s which has x=0.

f(x) is an odd function that is differentiable on I. show that f(0)=0 and f'(x) is even.

for part 2, f(x) is an even function with the same characteristics as part 1. show f'(x) is odd.

please show all the work for a thumbs up.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Let f be continuously differentiable function on the Reals with the following characteristics: - f(x) is...
Let f be continuously differentiable function on the Reals with the following characteristics: - f(x) is increasing from intervals (0,2) and (4,5) and decreasing everywhere else - f(x) > -1 on the interval (1,3) and f(x) < -1 everywhere else Suppose g(x) = 2f(x) + (f(x))^2. On which interval(s) is g(x) increasing?
suppose f is a differentiable function on interval (a,b) with f'(x) not equal to 1. show...
suppose f is a differentiable function on interval (a,b) with f'(x) not equal to 1. show that there exists at most one point c in the interval (a,b) such that f(c)=c
If f is a differentiable function such that f′(x) = (x^2− 16)*g(x), where g(x)>0 for all...
If f is a differentiable function such that f′(x) = (x^2− 16)*g(x), where g(x)>0 for all x, at which value(s) of x does f have a local maximum? 1. At both x=-4,4 2. Only at x=-16 3. Only at x=4 4. At both x=-16,16 5. Only at x=-4 6. Only at x=16
4a). Let g be continuous at x = 0. Show that f(x) = xg(x) is differentiable...
4a). Let g be continuous at x = 0. Show that f(x) = xg(x) is differentiable at x = 0 and f'(0) = g(0). 4b). Let f : (a,b) to R and p in (a,b). You may assume that f is differentiable on (a,b) and f ' is continuous at p. Show that f'(p) > 0 then there is delta > 0, such that f is strictly increasing on D(p,delta). Conclude that on D(p,delta) the function f has a differentiable...
Given that a function F is differentiable. a f(a) f1(a) 0 0 2 1 2 4...
Given that a function F is differentiable. a f(a) f1(a) 0 0 2 1 2 4 2 0 4 Find 'a' such that limx-->a(f(x)/2(x−a)) = 2. Provide with hypothesis and any results used.
PROVE USING IVT. Suppose f is a differentiable function on [s,t] and suppose f'(s) > 0...
PROVE USING IVT. Suppose f is a differentiable function on [s,t] and suppose f'(s) > 0 > f'(t). Then there's a point p in (s,t) where f'(p)=0.
Show that the function f(z) =x^3-3xy^2+i((3x^2y-y^3) is differentiable
Show that the function f(z) =x^3-3xy^2+i((3x^2y-y^3) is differentiable
Describe the x-values at which f is differentiable. (Enter your answer using interval notation.) f(x) =...
Describe the x-values at which f is differentiable. (Enter your answer using interval notation.) f(x) = x2 − 5,     x ≤ 0 5 − x2,     x > 0
Let f(x) be a continuous, everywhere differentiable function. What kind information does f'(x) provide regarding f(x)?...
Let f(x) be a continuous, everywhere differentiable function. What kind information does f'(x) provide regarding f(x)? Let f(x) be a continuous, everywhere differentiable function. What kind information does f''(x) provide regarding f(x)? Let f(x) be a continuous, everywhere differentiable function. What kind information does f''(x) provide regarding f'(x)? Let h(x) be a continuous function such that h(a) = m and h'(a) = 0. Is there enough evidence to conclude the point (a, m) must be a maximum or a minimum?...
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x)...
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = x3 + x − 9,    [0, 2] Yes, f is continuous on [0, 2] and differentiable on (0, 2) since polynomials are continuous and differentiable on .No, f is not continuous on [0, 2].    No, f is continuous on [0, 2] but not differentiable on (0, 2).Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem.There is...