Question

Find the solution of the given initial value problem: y(4)+2y′′+y=5t+2; y(0)=y′(0)=0, y′′(0)=y'''(0)=1

Find the solution of the given initial value problem:

y(4)+2y′′+y=5t+2; y(0)=y′(0)=0, y′′(0)=y'''(0)=1

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
find the solution of the given initial value problem 1. y''+y'−2y=0, y(0) =1, y'(0) =1 2....
find the solution of the given initial value problem 1. y''+y'−2y=0, y(0) =1, y'(0) =1 2. 6y''−5y'+y=0, y(0) =4, y'(0) =0 3. y''+5y'+3y=0, y(0) =1, y'(0) =0 4. y''+8y'−9y=0, y(1) =1, y'(1) =0
Find y(t) solution of the initial value problem 3ty^2y'-6y^3-4t^2=0, y(1)=1, t>0
Find y(t) solution of the initial value problem 3ty^2y'-6y^3-4t^2=0, y(1)=1, t>0
Find the first five nonzero terms in the solution of the given initial value problem. y′′+xy′+2y=0,...
Find the first five nonzero terms in the solution of the given initial value problem. y′′+xy′+2y=0, y(0)=5, y′(0)=9 Differential Equations
For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t)) and solve initial value problem y(0)...
For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t)) and solve initial value problem y(0) = -1/3
Find the solution of the initial value problem y′′+2y′+5y=16e^−tcos(2t), y(0)=6, y′(0)=0
Find the solution of the initial value problem y′′+2y′+5y=16e^−tcos(2t), y(0)=6, y′(0)=0
Consider the initial value problem dy dx = 1−2x 2y , y(0) = − √2 (a)...
Consider the initial value problem dy dx = 1−2x 2y , y(0) = − √2 (a) (6 points) Find the explicit solution to the initial value problem. (b) (3 points) Determine the interval in which the solution is defined.
Use Laplace transforms to solve the given initial value problem. y"-2y'+5y=1+t y(0)=0 y’(0)=4
Use Laplace transforms to solve the given initial value problem. y"-2y'+5y=1+t y(0)=0 y’(0)=4
Solve the initial value problem. d^2y/dx^2= -3 csc^2 x; y' (pi/4)=0; y(pi/2)=0 The solution is y=____.
Solve the initial value problem. d^2y/dx^2= -3 csc^2 x; y' (pi/4)=0; y(pi/2)=0 The solution is y=____.
find the general solution of the given differential equation 1. y''−2y'+2y=0 2. y''+6y'+13y=0 find the solution...
find the general solution of the given differential equation 1. y''−2y'+2y=0 2. y''+6y'+13y=0 find the solution of the given initial value problem 1. y''+4y=0, y(0) =0, y'(0) =1 2. y''−2y'+5y=0, y(π/2) =0, y'(π/2) =2 use the method of reduction of order to find a second solution of the given differential equation. 1. t^2 y''+3ty'+y=0, t > 0; y1(t) =t^−1
2. Find the solution of the initial value problem y''−y=0, y(0) = 5/4, y'(0) =−3/4.
2. Find the solution of the initial value problem y''−y=0, y(0) = 5/4, y'(0) =−3/4.