Find the steady-state vector for the matrix below: {0.7, 0.2, 0.2}, {0.1, 0.6, 0.1}, {0.2, 0.2, 0.7}
The numbers listed here are the rows of a 3x3 matrix.
The given matrix is A =
0.7 |
0.2 |
0.2 |
0.1 |
0.6 |
0.1 |
0.2 |
0.2 |
0.7 |
If X = (x,y,z)T is the steady state vector, then AX = X or, (A-I3)X = 0. To solve this equation, we need to reduce the matrix A-I3 to its RREF which is
1 |
0 |
-1 |
0 |
1 |
-0.5 |
0 |
0 |
0 |
Hence, the equation (A-I3)X = 0 is equivalent to x-z = 0 or, x = z and y-0.5z = 0 or, y = z/2. Then, X =(z,z/2,z)T =(z/2)(2,1,2)T.
Hence, (2,1,2)T is the steady state vector for the given matrix A.
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