Question

y^4 - y = 0 IVP (Initial Value Problem) y(0) = 0 y'(0) = 1 y''(0)...

y^4 - y = 0 IVP (Initial Value Problem)

y(0) = 0

y'(0) = 1

y''(0) = 0

y'''(0) = 0

The answer is y(t) = [sinh(t) + sin(t)] / 2 but I cannot figure out how to reach this.

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