Question

Find the arc length of r = θ 2 from θ = 2π to θ = 6π.

Answer #1

a.
r=3 - 3cos(Θ), enter value for r on a table
when;
Θ=0, (π/3),(π/2),(2π/3),π,(4π/3),(3π/2),(5π/3) & 2π
b. plot points from a, sketch graph
c. use calculus to find slope at (π/2),(2π/3),(5π/3)
& 2π
d. find EXACT area inside the curve in 1st
quadrant

Find the arc length of r(t) = from (1,0,0) to (-1,2,0)

. Find the arc length of the curve r(t) = <t^2 cos(t), t^2
sin(t)> from the point (0, 0) to (−π^2 , 0).

Find an arc length parametrization of r(t)=<3t^2,
2t^3>.
r(g(s))=<_______________, +-____________________>

An arc of length 200 ft subtends a central angle θ in a
circle of radius 50 ft. Find the measure of θ in degrees.
(Round your answer to one decimal place.)
θ = °
Find the measure of θ in radians.
θ = rad

Change from rectangular to cylindrical coordinates. (Let
r ≥ 0 and 0 ≤ θ ≤ 2π.)
(a) (-3,3,3)
(b) (-5,5sqrt(3),5)

Change from rectangular to cylindrical coordinates. (Let
r ≥ 0 and 0 ≤ θ ≤ 2π.)
(a) (-3,3,3)
(b) (-5,5sqrt(3),5)

Change from rectangular to cylindrical coordinates. (Let
r ≥ 0 and 0 ≤ θ ≤ 2π.)
(a) (3, −3, 5)
b) (-3,-3sqrt3,2)

Change from rectangular to cylindrical coordinates. (Let
r ≥ 0 and 0 ≤ θ ≤ 2π.)
(a).
(−9, 9, 9)
(b).
(-5,5sqrt(3), 9)

If θ is in the interval [0, 2π) and cos(θ) = √ 2/2 , then θ must
be π/4 .
State true or false.

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