Question

**A 3-phase, 380 V, 50 Hz , 6 pole, Y-connected induction
motor has R _{1} = 0.1**

**R _{2}^{’} = 0.12**

Answer #1

A 3-phase, 380 V, 50 Hz , 6 pole, Y-connected induction
motor has R1 = 0.1 W , X1 =
0.4 W,
R2’ = 0.12 W ,
X2’ = 0.4 W, Xm =
20 W , Pr = 1 kW. The motor is operated
at 970 rpm what is the output shaft torque?

The parameters of a 3-phase, 4-pole, 50 Hz,
Y-connected, wound-rotor induction motor are listed below. These
are the default values of the "Asynchronous Machine" model in
MATLAB Simulink. r1=0.5968 Ω; r2=0.6258 Ω; L1=0.0003495 H;
L2=0.005473 H; Lm=0.0354 H; Stator line voltage = 400 V rms. The
motor for rotor speeds nm= 0 to 1500 rpm.
X1= 0.1097 ohm, X2= 1.719 ohm , Xm= 11.12 ohm, RTH =
0.5853 , XTH = 0.1395 and
VTH = 230.82 V.
Suppose the motor...

The parameters of a 3-phase, 4-pole, 50 Hz, Y-connected,
wound-rotor induction motor are listed below. These are the default
values of the “Asynchronous Machine” model in MATLAB Simulink.
r1=0.5968 ?; r2=0.6258 ?; L1=0.0003495 H; L2=0.005473 H; Lm=0.0354
H; Stator line voltage = 400 V rms. The motor for rotor speeds nm=
0 to 1500 rpm. X1= 0.1097 ohm, X2= 1.719 ohm , Xm= 11.12 ohm, RTH =
0.5853 , XTH = 0.1395 and VTH = 230.82 V. Suppose the motor...

A 480V, 60 Hz, 6-pole, three-phase, delta-connected induction
motor has the following parameters: R1=0.461 Ω, R2=0.258 Ω,
X1=0.507 Ω, X2=0.309 Ω, Xm=30.74 Ω Rotational losses are 2450W.
Core loss is neglected. The motor drives a mechanical load at a
speed of 1170 rpm.
Ns = 1200rpm
slip = 0.025
Line current = 26.87 angle -0.38
Pin = 20.745KW
Airgap power = 19.71KW
Converted power = 19.21KW
Torque = 156.85Nm
Pout = 16.76KW
efficiency = 80.79%
Find : 1. Pullout slip...

A three phase Wye-connected 460 v, 4 poles, 60 Hz wound rotor
induction motor has the following parameters:
R1=0.3, R2=0.15, X1=0.5,
X2=0.2, Xm=14
The total friction, windage, and core loss is constant at 400 w.
The motor is working at its rated voltage and drives its load at
1764 rpm.
a)Calculate the input current and the input power.
b)Calculate the output mechanical power and torque and motor
efficiency.
c)Calculate the starting current of this motor and compare it
with its...

A three-phase, 280 V, 60 Hz, 20 hp, 1710 r/m. Y-connected
induction motor has the following impedances in ohms per phase
referred to the stator circuit:
R1=0.12 Ω.
Rˈ2=0.1
Ω
X1=Xˈ2=0.25 Ω
Xm=10 Ω
A total rotational loss are 400 W. The core loss is lumped in
with the rotational losses. For a slip of 0.05 at the rated voltage
and rated frequency. Find:
a) The numbers of poles of the motor.
b) The stator current.
c) the power factor...

A 230 volt, 60 Hz, 4 pole star connected, three phase induction
motor operates at a full load speed of 1710 rpm. The power
developed at this speed is 2 horse power. If the supply voltage
fluctuates ±10%, determine the torque range of the motor.

Q1. A 440 V, 60 Hz, six-pole, 3 phase induction motor is taking
50 kVA at 0.8 power
factor and is running at a slip of 2.5 percent. The stator copper
losses are 0.5 kW and
rotational losses are 2.5 kW.
i) The rotor copper losses
ii) The shaft hp
iii) The efficiency
iv) The shaft torque

a 3 phase Y connected , 208v line to line, 60 HZ, 6 poles
induction machine operates at 1152 rpm. this machine has parameters
R1= 0.25 OHM, R'2= 0.15 OHM , AND X1=X'2=0.25ohm . tyhe rotaional
loss is 300 w.
A)rated mechanical torque
b) the starting mechanical torque
c)the output shaft horsepower

Q4)
A three-phase, 104 kW, 3300 V, 50 Hz, Y-connected induction
motor delivers full output power to a
load connected to its shaft. The full-load slip is 0.02 and
full-load power factor is 0.85 lagging. If the stator
copper loss is 2400 W, the stator core loss is 3500 W, and the
friction and windage loss is 1200 W. Calculate:
(i) The developed mechanical power.
(ii) The air gap power.
(iii) The rotor copper loss.
(iv) The efficiency of the...

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