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A 480V, 60 Hz, 6-pole, three-phase, delta-connected induction motor has the following parameters: R1=0.461 Ω, R2=0.258...

A 480V, 60 Hz, 6-pole, three-phase, delta-connected induction motor has the following parameters: R1=0.461 Ω, R2=0.258 Ω, X1=0.507 Ω, X2=0.309 Ω, Xm=30.74 Ω Rotational losses are 2450W. Core loss is neglected. The motor drives a mechanical load at a speed of 1170 rpm.

Ns = 1200rpm

slip = 0.025

Line current = 26.87 angle -0.38

Pin = 20.745KW

Airgap power = 19.71KW

Converted power = 19.21KW

Torque = 156.85Nm

Pout = 16.76KW

efficiency = 80.79%

Find : 1. Pullout slip

2. Pull out torque

3. Start torque

I need the solution with full calculations and formulas.

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