Question

A three-phase, 280 V, 60 Hz, 20 hp, 1710 r/m. Y-connected induction motor has the following...

A three-phase, 280 V, 60 Hz, 20 hp, 1710 r/m. Y-connected induction motor has the following impedances in ohms per phase referred to the stator circuit:

R1=0.12 Ω.                Rˈ2=0.1 Ω

X1=Xˈ2=0.25 Ω        Xm=10 Ω

A total rotational loss are 400 W. The core loss is lumped in with the rotational losses. For a slip of 0.05 at the rated voltage and rated frequency. Find:

a) The numbers of poles of the motor.

b) The stator current.

c) the power factor of the motor.

d) The input power of the motor.

e) The developed mechanical power.

f) The efficiency of the motor.

Engineering   Electrical-Engineering   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 480V, 60 Hz, 6-pole, three-phase, delta-connected induction motor has the following parameters: R1=0.461 Ω, R2=0.258...
A 480V, 60 Hz, 6-pole, three-phase, delta-connected induction motor has the following parameters: R1=0.461 Ω, R2=0.258 Ω, X1=0.507 Ω, X2=0.309 Ω, Xm=30.74 Ω Rotational losses are 2450W. Core loss is neglected. The motor drives a mechanical load at a speed of 1170 rpm. Ns = 1200rpm slip = 0.025 Line current = 26.87 angle -0.38 Pin = 20.745KW Airgap power = 19.71KW Converted power = 19.21KW Torque = 156.85Nm Pout = 16.76KW efficiency = 80.79% Find : 1. Pullout slip...
A three phase Wye-connected 460 v, 4 poles, 60 Hz wound rotor induction motor has the...
A three phase Wye-connected 460 v, 4 poles, 60 Hz wound rotor induction motor has the following parameters: R1=0.3, R2=0.15, X1=0.5, X2=0.2, Xm=14 The total friction, windage, and core loss is constant at 400 w. The motor is working at its rated voltage and drives its load at 1764 rpm. a)Calculate the input current and the input power. b)Calculate the output mechanical power and torque and motor efficiency. c)Calculate the starting current of this motor and compare it with its...
A 208 V 10 Hp four pole 60 Hz Y connected induction motor has a full...
A 208 V 10 Hp four pole 60 Hz Y connected induction motor has a full load slip of 5%. What is the output power of this motor in kW? If friction and windage loss is 350 watts, what is the gross mechanical output at full load? What is the gross torque of this motor at full load? What is the rotor cupper loss at full load? If the efficiency of this motor is 90% at full load what is...
The following test data apply to a 7.5-hp, three-phase, 220-V, 19-A,60-Hz, four-pole induction motor with a...
The following test data apply to a 7.5-hp, three-phase, 220-V, 19-A,60-Hz, four-pole induction motor with a double-squirrel-cage rotor of design class C (high-starting-torque, low-starting current type): Test 1: No-load test at 60 Hz; Applied voltage V = 219 V line-to-line; Average phase current I1,nl = 5.70 A; Power Pnl =380 W; Test 2: Blocked-rotor test at 15 Hz; Applied voltage V = 26.5 V line-to-line; Average phase current ll,bl = 18.57 A; Power Pbl = 675 W; Test 3: Average...
Q4) A three-phase, 104 kW, 3300 V, 50 Hz, Y-connected induction motor delivers full output power...
Q4) A three-phase, 104 kW, 3300 V, 50 Hz, Y-connected induction motor delivers full output power to a load connected to its shaft. The full-load slip is 0.02 and full-load power factor is 0.85 lagging. If the stator copper loss is 2400 W, the stator core loss is 3500 W, and the friction and windage loss is 1200 W. Calculate: (i) The developed mechanical power. (ii) The air gap power. (iii) The rotor copper loss. (iv) The efficiency of the...
A 400V, 2 pole, 50 Hz, three-phase induction motor is drawing 60 A at 0.85 PF...
A 400V, 2 pole, 50 Hz, three-phase induction motor is drawing 60 A at 0.85 PF lagging. The stator copper losses are 2 kW, the stator core losses are 1.8 kW and rotor copper losses are 700 W. The friction and windage losses are 600 W, the stray loss 100 W, and rotor core loss 100 W. Find the following quantities: a. The air gap power. b. The developed mechanical power. c. The output power. d. The efficiency of the...
A three-phase wye-connected (Y) synchronous generator is operating at Ea = 8.OLO° kV (lineneutral) and has...
A three-phase wye-connected (Y) synchronous generator is operating at Ea = 8.OLO° kV (lineneutral) and has synchronous reactance of X~ = 1.0 fl . The generator is connected to a threephase delta-wye connected step-down transformer that is constructed from three individual single-phase transformers. Each the single-phase transformers has rated power of 200 kVA has a turns ratio of 4:1 where the rated primary voltage of 8.0 kV and a rated secondary of 2.0 kV and a per-unit series reactance of...
Q1. A 440 V, 60 Hz, six-pole, 3 phase induction motor is taking 50 kVA at...
Q1. A 440 V, 60 Hz, six-pole, 3 phase induction motor is taking 50 kVA at 0.8 power factor and is running at a slip of 2.5 percent. The stator copper losses are 0.5 kW and rotational losses are 2.5 kW. i) The rotor copper losses ii) The shaft hp iii) The efficiency iv) The shaft torque
Question2: Calculate the total machine losses under this condition: A 415V, 50Hz, 2790rpm, 3 phase, star-connected...
Question2: Calculate the total machine losses under this condition: A 415V, 50Hz, 2790rpm, 3 phase, star-connected induction motor has the following equivalent circuit parameters (all referred to the stator winding) : stator leakage reactance X1= 0.3 ohm, stator resistance R1= 0.2 ohms, rotor leakage reactance X2' = 0.3 ohm, rotor resistance R2' = 0.16 ohm, magnetising reactance XM = 12 ohm, core-loss resistance = 150 ohms. Use the simplified equivalent circuit for the following calculations. Under a certain operating condition...
A 100 KW (OUT PUT), 3300V, 50 Hz, 3-Phase star connected induction motor has a synchronous...
A 100 KW (OUT PUT), 3300V, 50 Hz, 3-Phase star connected induction motor has a synchronous speed of 500 rpm. The full load slip is 1.8%and full load power factor 0.85. Stator copper loss=2440W. Iron loss=3500W. Rotational losses= 1200W. calculate : The rotor copper loss The line current The full load motor efficiency.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT