In Problem 12, Al’s production function for deer is f(x1, x2) = (2x1 + x2)1/2, where x1 is the amount of plastic and x2 is the amount of wood used. If the cost of plastic is $8 per unit and the cost of wood is $1 per unit, then the cost of producing 7 deer is
a. |
$49. |
|
b. |
$28. |
|
c. |
$196. |
|
d. |
$7. |
|
e. |
$119. |
step by step, please
Option (a).
Q = f(x1, x2) = (2x1 + x2)1/2
(2x1 + x2)1/2 = 7
Squaring both sides,
2x1 + x2 = 49
Total cost (TC) = w1.x1 + w2.x2
TC ($) = 8x1 + x2
For a linear production function, the inputs are substitutes and isoquant is a straight line touching both axes. Optimal input combination lies at one of the corner points (i.e. either x1 or x2 will be used).
From production function,
When x1 = 0, x2 = 49 and TC ($) = 8 x 0 + 49 = 49
When x2 = 0, x1 = 49/2 = 24.5 and TC ($) = 8 x 24.5 + 0 = 196
Since TC is lower when x1 = 0 and x2 = 49, this is optimal input combination with total cost of $49.
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