Question

Using a loop, complete the following method so that it goes through the array from left to right, one element at a time and replaces that element with the sum of itself and the next element in the array (if there is a next element). For example, if the input is {1, 3, 5} the output must be {4, 8, 5} -- on the first iteration 1 was replaced by 1+3; on the second iteration 3 was replaced by 3+5.

public static void addNextItem(int[] arr)
{
        
}

Answer 1

public static void addNextItem(int[] arr) {
    for (int i = 0; i < arr.length - 1; i++) {
        arr[i] += arr[i + 1];
    }
}

import java.util.Arrays;

public class AddNextItemTest {

    public static void addNextItem(int[] arr) {
        for (int i = 0; i < arr.length - 1; i++) {
            arr[i] += arr[i + 1];
        }
    }

    public static void main(String[] args) {
        int[] arr = {1, 3, 5};
        System.out.println(Arrays.toString(arr));
        addNextItem(arr);
        System.out.println(Arrays.toString(arr));
    }
}