Question

A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts of mercury​ (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 98 98​% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna​ sushi? 0.56    0.77    0.10    0.98    1.27   0.52    0.89 What is the confidence interval estimate of the population mean mu μ​?

Answer 1

solution:

first of all compute the mean and standard deviation of the given sampled data

so mean =

standard deviation =

confidence leve = CL = 98% = 0.98

since population standard deviation is not known and sample size is small we will use t distribution to find confidence interval

df = n - 1 = 7 - 1 = 6

critical value of t =

margin of error = E =

confidence interval of the mean =

upper limit = 0.73 + 0.45 = 1.18

lower limit = 0.73 - 0.45 = 0.28

Yes there is a chance of having a greater of equal to 1 ppm murcury in the population because the upper bound of mean is 1.18 ppm