Question

a.) Simplify f(w, x, y) = (wx + y')(w' + x' + y). You need to show step-by-steps to your final answer.

Answer 1

Solution:

(a)

Given,

=>f(w, x, y) = (wx + y')(w' + x' + y)

Explanation:

Simplification of function:

=>f(w, x, y) = (wx + y')(w' + x' + y)

Multiply both the terms

=>f(w, x, y) = wxw' + wxx' + wxy + y'w' + y'x' + y'y

=>f(w, x, y) = ww'x + wxx' + wxy + w'y' + x'y' + yy'

We know that ww' = 0, xx' = 0, yy' = 0

=>f(w, x, y) = 0.x + w.0 + wxy + w'y' + x'y' + 0

=>f(w, x, y) = 0 + 0 + wxy + w'y' + x'y'

=>f(w, x, y) = wxy + w'y' + x'y'

=>Hence simplified expression is: f(w, x, y) = wxy + w'y' + x'y'

I have explained each and every part with the help of statements attached to it.