7. Convert 7E2516 to base 10.
8. The range of positive integers possible in an 8-bit two’s complement system is (Read this question carefully):
Question 8 options:
1 to 256 |
|
1 to 127 |
|
-128 to 127 |
|
1 to 128 |
7.
Start at the rightmost digit. Convert that digit to decimal and multiply with 160 (20 = 1). Convert second digit to decimal and multiply with 161, third digit multiply with 162...
Add together all products
5 + 32 + 3584 + 28672 = 32293
Answer:
32293
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8.
The range of positive integers possible in an 8-bit two’s complement system is -128 to 127
Answer:
-128 to 127 |
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