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Convert -39 (base 10) to 8-bit binary using excess 127 notation.

Convert -39 (base 10) to 8-bit binary using excess 127 notation.

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Answer #1

Hey there!

To convert a base 10 (decimal) number to 8 bit binary using excess 127 notation :

Step 1 : Add 127 to the number

-39 + 127 = 88

Step 2 : Convert the result of the addition to binary number

This can be done by repeatedly dividing the number by 2 as shown below

The obtained binary number is not 8 bit. So we add zero to the left.

01011000

Therefore the answer : 8 bit binary representation of -39(10) using excess 127 = 01011000

Please let me know in the comments , if you have any queries . Consider giving a thumbs up! Thanks :)

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