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Write a program in ARM assembly language that copies each element of array A to consecutive fourth elements of array B, i.e., A[0] to B[0], A[1] to B[3], A[2] to B[7], etc. The array A is 12 elements long, and each element is a number that is 32 bits (1 word) wide. Assume the base address of array A is in register R2, and the base address of array B is in R3.

Answer #1

**Answer : Given data**

* The program in ARM assembly language that copies each element of array A to consecutive fourth elements of array B, i.e., A[0] to B[0], A[1] to B[3], A[2] to B[7], etc

The required program snippet for the above operation in ARM assembly with R2 as base address of array A snd R3 as base address of array B is as below.

*** MOV R4,#0** ; initialise loop counter

*** LOOP LDR R5,[R2],#4** ;load the word content
32bit array A element to R5 register and post increment R2 to point
to nextvelement of array A

*** STR R5,[R3],#16** ;Store the word content 32bit
into array B element from R5 register and post increment R3 to
point to next 4th consicutive element of array B

*** ADD R4,R4,#1** ; increment loop counter

*** CMP R4,#12** ; checking condition for 12
elements

*** BNE LOOP** ; repeats loop for 12 times till r4
is 12\

___________**THE END**_____________

Write a program in ARM assembly language that copies each
element of array A to consecutive fourth elements of array B, i.e.,
A[0] to B[0], A[1] to B[3], A[2] to B[7], etc. The array A is 12
elements long, and each element is a number that is 32 bits (1
word) wide. Assume the base address of array A is in register R2,
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