Question

Write a function int count_consonants(char str[]) that determines and returns the number of consonants in a given string.
Then write a simple main() function where you can repeatedly enter a string and then the num- ber of consonants is determined and printed on the screen (from the main() function). If the entered string is empty (it will contain only a ’\n’ then) the program should stop its execution. You can safely assume that the entered string will be not longer than 100 characters and will be valid.

Your solution has to satisfy the requirements from the problem description and has to pass the following testcase and potentially other testcases which are uploaded. All characters are relevant for passing testcases including newlines and spaces.

Answer 1

The explanation is clearly provided in the comments of the code itself.

CODE--

#include<bits/stdc++.h>
using namespace std;
int count_consonants(char str[])
{
   //declare a variable to keep a count of the consonants
   int consonants=0;
   //iterate over the str
   int i=0;
   while(str[i]!='\0')
   {
       //check for consonants
       if(str[i]!='a' && str[i]!='e' && str[i]!='i' && str[i]!='o' && str[i]!='u' && str[i]!='A' && str[i]!='E' && str[i]!='I' && str[i]!='O' && str[i]!='U')
       {
           consonants++;
       }
       //increment iterator
       i++;
   }
   //finally return the count
   return consonants;
}
int main()
{
   while(true)
   {
       char str[100];
       //get input from the user
       cout<<"Enter -1 to exit\n";
       cout<<"Enter a string:\n";
       cin.getline(str,100);
       //check exit condition
       if(str[0]=='-'&&str[1]=='1'&&str[2]=='\0')
       {
           cout<<"Thank You...!\n";
           break;
       }
       //display the output
       cout<<"Number of consonants = "<<count_consonants(str)<<endl<<endl;
   }
}

OUTPUT SCRENSHOT--

NOTE--

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